Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.9 Curvature and Normal Vectors - 11.9 Exercises - Page 852: 25

Answer

\[\kappa = \frac{{2\sqrt 5 }}{{{{\left( {20{{\sin }^2}t + {{\cos }^2}t} \right)}^{3/2}}}}\]

Work Step by Step

\[\begin{gathered} {\mathbf{r}}\left( t \right) = \left\langle {4\cos t,\sin t,2\cos t} \right\rangle \hfill \\ {\text{Calculate }}{\mathbf{v}}\left( t \right){\text{ and }}\left| {{\mathbf{v}}\left( t \right)} \right| \hfill \\ {\mathbf{v}}\left( t \right) = {\mathbf{r}}'\left( t \right) \hfill \\ {\mathbf{v}}\left( t \right) = \frac{d}{{dt}}\left\langle {4\cos t,\sin t,2\cos t} \right\rangle \hfill \\ {\mathbf{v}}\left( t \right) = \left\langle { - 4\sin t,\cos t, - 2\sin t} \right\rangle \hfill \\ \left| {{\mathbf{v}}\left( t \right)} \right| = \sqrt {{{\left( { - 4\sin t} \right)}^2} + {{\left( {\cos t} \right)}^2} + {{\left( { - 2\sin t} \right)}^2}} \hfill \\ \left| {{\mathbf{v}}\left( t \right)} \right| = \sqrt {16{{\sin }^2}t + {{\cos }^2}t + 4{{\sin }^2}t} \hfill \\ \left| {{\mathbf{v}}\left( t \right)} \right| = \sqrt {20{{\sin }^2}t + {{\cos }^2}t} \hfill \\ \hfill \\ {\text{Calculate }}{\mathbf{a}}\left( t \right) \hfill \\ {\mathbf{a}}\left( t \right) = {\mathbf{v}}'\left( t \right) \hfill \\ {\mathbf{a}}\left( t \right) = \frac{d}{{dt}}\left\langle { - 4\sin t,\cos t, - 2\sin t} \right\rangle \hfill \\ {\mathbf{a}}\left( t \right) = \left\langle { - 4\cos t, - \sin t, - 2\cos t} \right\rangle \hfill \\ \hfill \\ {\text{Calculate }}\left| {{\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right)} \right| \hfill \\ {\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right) = \left| {\begin{array}{*{20}{c}} {\mathbf{i}}&{\mathbf{j}}&{\mathbf{k}} \\ { - 4\sin t}&{\cos t}&{ - 2\sin t} \\ { - 4\cos t}&{ - \sin t}&{ - 2\cos t} \end{array}} \right| \hfill \\ {\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right) = \left| {\begin{array}{*{20}{c}} {\cos t}&{ - 2\sin t} \\ { - \sin t}&{ - 2\cos t} \end{array}} \right|{\mathbf{i}} - \left| {\begin{array}{*{20}{c}} { - 4\sin t}&{ - 2\sin t} \\ { - 4\cos t}&{ - 2\cos t} \end{array}} \right|{\mathbf{j}} \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, + \left| {\begin{array}{*{20}{c}} { - 4\sin t}&{\cos t} \\ { - 4\cos t}&{ - \sin t} \end{array}} \right|{\mathbf{k}} \hfill \\ {\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right) = \left( { - 2{{\cos }^2}t - 2{{\sin }^2}t} \right){\mathbf{i}} - \left( {8\sin t\cos t - 8\sin t\cos t} \right){\mathbf{j}} \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, + \left( {4{{\sin }^2}t + 4{{\cos }^2}t} \right){\mathbf{k}} \hfill \\ {\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right) = - 2{\mathbf{i}} + 0{\mathbf{j}} + 4{\mathbf{k}} \hfill \\ \left| {{\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right)} \right| = \sqrt {4 + 16} \hfill \\ \left| {{\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right)} \right| = \sqrt {20} \hfill \\ \left| {{\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right)} \right| = 2\sqrt 5 \hfill \\ \hfill \\ {\text{Use the alternative curvature formula}} \hfill \\ \kappa = \frac{{\left| {{\mathbf{v}}\left( t \right) \times {\mathbf{a}}\left( t \right)} \right|}}{{{{\left| {{\mathbf{v}}\left( t \right)} \right|}^3}}} \hfill \\ \kappa = \frac{{2\sqrt 5 }}{{{{\left( {\sqrt {20{{\sin }^2}t + {{\cos }^2}t} } \right)}^3}}} \hfill \\ \kappa = \frac{{2\sqrt 5 }}{{{{\left( {20{{\sin }^2}t + {{\cos }^2}t} \right)}^{3/2}}}} \hfill \\ \end{gathered} \]
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.