Work Step by Step
$(f ∘ g)(x) = x^4 + 3$ $g(x)=x^2+3$ $(f ∘ g)(x) = f(g(x)) = f(x^2+3) =x^4 + 3$ Therefore lets choose $f(x) =(x-3)^2+3$ $(f ∘ g)(x) = f(g(x)) =(g(x)-3)^2+3=(x^2+3-3)^2+3= (x^2)^2+3=x^4+3$
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