Answer
$f(x) =(x-3)^2+3$
Work Step by Step
$(f ∘ g)(x) = x^4 + 3$
$g(x)=x^2+3$
$(f ∘ g)(x) = f(g(x)) = f(x^2+3) =x^4 + 3$
Therefore lets choose $f(x) =(x-3)^2+3$
$(f ∘ g)(x) = f(g(x)) =(g(x)-3)^2+3=(x^2+3-3)^2+3= (x^2)^2+3=x^4+3$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 10: 53
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