Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 10: 36



Work Step by Step

We know that $F(x)=1/(x-3)$, so: $F(\frac{3x+1}{x})=F(3+1/x)=1/(3+1/x-3)=1/(1/x)=x$
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