## Calculus: Early Transcendentals (2nd Edition)

$g(x)=x^4+2$ and $f(x)=\sqrt{x}$ The domain of $h$ is $\mathbb{R}$
If we set $g(x)=x^4+2$ and $f(x)=\sqrt{x}$, then: $f(g(x))=\sqrt{x^4+2}$ The domain of $h$ is $\mathbb{R}$ (because the inside of the radical is never negative).