Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises: 35

Answer

$x$

Work Step by Step

We know that $f(x)=x^2-4$, so: $f(\sqrt{x+4})=(\sqrt{x+4})^2-4=x+4-4=x$
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