Answer
Domain: (-$\infty$, -2) U (-2, 3) U (3, $\infty$)
Range: (-$\infty$, $\infty$)
Work Step by Step
In order to achieve the domain, the denominator cannot be equal to 0, so solve:
0$\ne$(y+2)(y-3)
y+2$\ne$0
y$\ne$-2
y-3$\ne$0
y$\ne$3
Set into interval notation these values make: (-$\infty$, -2) U (-2, 3) U (3, $\infty$)
To find the range, it can be observed from the graph that the lines extend upwards and downwards continuously, therefore, the range is (-$\infty$, $\infty$)
