## Calculus 8th Edition

$\int ye^{0.2y}dy$ Let $u=y$ and $dv=e^{0.2y}dy$ then $du=dy$ and $v=\frac{e^{0.2y}}{0.2}=5e^{0.2y}$ and therefore \begin{equation*} \int ye^{0.2y}dy=5ye^{0.2y}-\int 5e^{0.2y}dy \end{equation*} \begin{equation*} =5ye^{0.2y}-25e^{0.2y}+C \end{equation*}