Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - Review - Exercises - Page 505: 37


$$y'=\sinh \left(x^2\right)+2x^2\cosh \left(x^2\right)$$

Work Step by Step

Given $$y= x\sinh(x^2)$$ Then \begin{align*} y'&=\frac{d}{dx}\left(x\right)\sinh \left(x^2\right)+\frac{d}{dx}\left(\sinh \left(x^2\right)\right)x\\ &=\sinh \left(x^2\right)+2x^2\cosh \left(x^2\right) \end{align*}
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