Answer
$$y'=\sinh \left(x^2\right)+2x^2\cosh \left(x^2\right)$$
Work Step by Step
Given $$y= x\sinh(x^2)$$
Then
\begin{align*}
y'&=\frac{d}{dx}\left(x\right)\sinh \left(x^2\right)+\frac{d}{dx}\left(\sinh \left(x^2\right)\right)x\\
&=\sinh \left(x^2\right)+2x^2\cosh \left(x^2\right)
\end{align*}
