Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - Review - Exercises - Page 505: 22



Work Step by Step

Given $$g(t)=\frac{e^t}{1+e^t}$$ Then \begin{align*} g'(t)&= \frac{\frac{d}{dt}\left(e^t\right)\left(1+e^t\right)-\frac{d}{dt}\left(1+e^t\right)e^t}{\left(1+e^t\right)^2}\\ &=\frac{e^t\left(1+e^t\right)-e^te^t}{\left(1+e^t\right)^2}\\ &=\frac{e^t}{\left(1+e^t\right)^2} \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.