Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - Review - Exercises - Page 505: 29

Answer

$$y'=2\tan x$$

Work Step by Step

Given $$y=\ln\left(sec^{2\:}x\right)$$ Then \begin{align*} y'&=\frac{1}{\sec ^2\left(x\right)}\cdot \:2\sec ^2\left(x\right)\tan \left(x\right)\\ &=2\tan x \end{align*}
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