Answer
(a) $7$
(b)$\frac{1}{8}$
Work Step by Step
(a) Since $ f(7)=3$ , then $f^{-1}(3)=7$
(b) since
\begin{align*}
(f^{-1})'(3)&=\frac{1}{f'(f^-1(3))}\\
&=\frac{1}{f'(7)}\\
&=\frac{1}{8}
\end{align*}
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