Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - Review - Exercises - Page 505: 3


(a) $7$ (b)$\frac{1}{8}$

Work Step by Step

(a) Since $ f(7)=3$ , then $f^{-1}(3)=7$ (b) since \begin{align*} (f^{-1})'(3)&=\frac{1}{f'(f^-1(3))}\\ &=\frac{1}{f'(7)}\\ &=\frac{1}{8} \end{align*}
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