## Calculus 8th Edition

(a) $\pi$ (b) $\dfrac{\sqrt{3}}{3}$
Given (a) $\ln e^{\pi}$ Since $\ln x^a=a\ln x$, then $\ln e^{\pi}=\pi \ln e=\pi$ (b)$\tan(\arcsin 1 /2)$ Since $\arcsin (1 /2)=\frac{\pi }{6}$, then $\tan(\pi/6) =\frac{\sqrt{3}}{3}$