Answer
$ D=x \in \mathbb R; -2 \lt x \lt 2$
Work Step by Step
The domain of the logarithm function is:
$$ D=x \in \mathbb R; 4-x^{2} \gt 0$$
$$ D=x \in \mathbb R; (2-x)(2+x) \gt 0$$
We get the result:
$$ D=x \in \mathbb R; -2 \lt x \lt 2$$
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