Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.3 Logarithmic Functions - 6.3 Exercises - Page 427: 50

Answer

$-\infty$

Work Step by Step

$$\lim_{x \to 0^{+}}\ln(\sin(x))=\ln(\lim_{x \to 0^{+}}(\sin(x))$$ Since $\lim_{x \to 0^{+}}(\sin(x))=0$ it follows: $$\ln(\lim_{x \to 0^{+}}(\sin(x))=\lim_{x \to 0}\ln (x)=-\infty$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.