Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.3 Logarithmic Functions - 6.3 Exercises - Page 427: 27


(a) $x=(\frac{7-ln6}{4})$ (b)$x=\frac{1}{3}(10+e^{2})$

Work Step by Step

(a) Given: $e^{7-4x}=6$ Take logarithms to both sides. $(7-4x)=ln6$ This implies $x=(\frac{7-ln6}{4})$ (b) Given: $ln(3x-10)=2$ $3x-10=e^{2}$ Hence, $x=\frac{1}{3}(10+e^{2})$
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