## Calculus 8th Edition

$ln3$
Solve each equation for $x$. Given: $e^{2x}-e^{x}-6=0$ $(e^{x}+2)(e^{x}-3)=0$ Thus, $e^{x}=3$ or $e^{x}=-2$ Consider positive term we have $e^{x}=3$ This implies $x=ln3$ Hence, $x=ln3$