## Calculus 8th Edition

Published by Cengage

# Chapter 14 - Partial Derivatives - Review - Exercises - Page 1023: 32

#### Answer

$du=\dfrac{e^{2t}}{(1+se^{2t})}ds+\dfrac{2se^{2t}}{(1+se^{2t})}dt$

#### Work Step by Step

Given: $u=ln(1+se^{2t})$ $du=f_s(s,t)ds+f_t(s,t)dt$ Thus, $du=\dfrac{e^{2t}}{(1+se^{2t})}ds+\dfrac{2se^{2t}}{(1+se^{2t})}dt$

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