## Calculus 8th Edition

$\frac{\partial C}{\partial T}=3.587$ $\frac{\partial C}{\partial S}=1.24$ and $\frac{\partial C}{\partial D}=0.016$
$\frac{\partial C}{\partial T}=4.6-2\times 0.055\times T+3\times 0.00029\times T^2-0.01(S-35)=3.587$ Substitute $T=10$ and $S=35$ $\frac{\partial C}{\partial T}=4.6-2\times 0.055\times 10+3\times 0.00029\times 10^2-0.01(35-35)=3.587$ $\frac{\partial C}{\partial S}=1.34-0.01(10)=1.24$ and $\frac{\partial C}{\partial D}=0.016$