Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 14 - Partial Derivatives - Review - Exercises - Page 1023: 27


(a) $2x-2y-3z=3$ (b) $\frac{x-2}{4}=\frac{y+1}{-4}=\frac{z-1}{-6}$

Work Step by Step

$x^2+2y^2-3z^2=3$ and $(2,-1,1)$ (a) Equation for a tangent plane is given as: $4(x-2)+(-4)(y+1)+(-6)(z-1)=0$ $4x-4y-6z=6$ $2x-2y-3z=3$ (b) $2x-2y-3z=3$ Equation of normal line is: $\frac{x-2}{4}=\frac{y+1}{-4}=\frac{z-1}{-6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.