## Calculus 8th Edition

$x=1+5t,y=2t,z=-3t$ and $\frac{x-1}{5}=\frac{y}{2}=\frac{-z}{3}$
We will find the point of intersection between two planes. In order to find this, take $z=0$ Parametric equations are defined by: $x=x_0+at$, $y=y_0=bt$ and $z=z_0+ct$ Thus, the parametric equations are: $x=1+5t,y=2t,z=-3t$ The symmetric equations are defined by: $\frac{x-x_0}{a}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$ Hence, the symmetric equations are: $\frac{x-1}{5}=\frac{y}{2}=\frac{-z}{3}$