Answer
$5x-3y-8z=-9$
Work Step by Step
The general form of the equation of the plane passing through the point $(a,b,c)$ and having normal vector $\lt l,m,n\gt$is:
$l(x-a)+m(y-b)+n(z-c)=0$
Thus, the equation of plane is:
$25(x-2)-15(y-1)-40(z-2)=0$
$5(x-2)-3(y-1)-8(z-2)=0$
After simplification, we get
$5x-3y-8z+9=0$
Or, $5x-3y-8z=-9$
