Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - 12.5 Equations of Lines and Planes - 12.5 Exercises - Page 871: 4

Answer

$r=\lt2,14-3t,-10+9t\gt$ and $x=2t,y=14-3t,z=-10+9t $

Work Step by Step

Equation of the line is given by $r=r_0+tv$ $r=(0,14,-10) $ Thus, the vector equation of the line is $r=(0,14,-10)+t\lt2,-3,9\gt$ $r=\lt2,14-3t,-10+9t\gt$ Hence, the parametric equations are: $x=2t,y=14-3t,z=-10+9t $
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