Answer
$3x+2y-5z=0$
Work Step by Step
The general form of the equation of the plane is:
$x+ay+bz=c$
Since, the plane passes through the origin, thus, $c=0$
$x+ay+bz=0$
Plugging in the values $(3,-2,1)$, we get
$3+a(-2)+b(1)=0$
$3-2a+b=0$
$2a-b=3$ ...(1)
Plugging in the values $(1,1,1)$, we get
$1+a(1)+b(1)=0$
$a+b=-1$...(2)
Add equations (1) and (2), after simplification, we get
$3x+2y-5z=0$