## Calculus 8th Edition

Area of a parallelogram with vertices $ABCD$ is defined as: $|{AB} ^{ \to} \times {AD}^{ \to}|$ Here, ${AB} ^{ \to} =\lt 3-(-3),-1-0 \gt= \lt 6,-1 \gt$ ${AD} ^{ \to} =\lt -1-(-3),3-0 \gt= \lt 2,3 \gt$ $|{AB} ^{ \to} \times {AD}^{ \to}|=\lt 6,-1 \gt \times \lt 2,3 \gt$ $=6(3)-(-1)2$ $=18-(-2)$ $=20$ units