Answer
20 units
Work Step by Step
Area of a parallelogram with vertices $ABCD$ is defined as:
$|{AB} ^{ \to} \times {AD}^{ \to}|$
Here,
${AB} ^{ \to} =\lt 3-(-3),-1-0 \gt= \lt 6,-1 \gt$
${AD} ^{ \to} =\lt -1-(-3),3-0 \gt= \lt 2,3 \gt$
$|{AB} ^{ \to} \times {AD}^{ \to}|=\lt 6,-1 \gt \times \lt 2,3 \gt $
$=6(3)-(-1)2$
$=18-(-2)$
$=20$ units