## Calculus 8th Edition

$\sqrt {269}$ units
Area of a parallelogram with vertices $PQRS$ is defined as: $|{PQ} ^{ \to} \times {PS}^{ \to}|$ Here, ${PQ} ^{ \to} = \lt 2,3 ,1\gt$ ${PS} ^{ \to} = \lt 4,2,5 \gt$ ${PQ} ^{ \to} \times {PS}^{ \to}=|\lt 2,3,1 \gt \times \lt 4,2,5 \gt| = \lt 13,-6,-8 \gt$ $|{PQ} ^{ \to} \times {PS}^{ \to}|=|\sqrt {13^2+(-6)^2+(-8)^2}|$ $= |\sqrt {169+36+64}|$ $=\sqrt {269}$ units