Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.2 Series - 11.2 Exercises: 51

Answer

$|r|=\frac{1}{10}<1$ Convergent $S=\frac{8}{9}$

Work Step by Step

$0.\bar{8}=0.8888...=\Sigma \frac{8}{10^n}=\Sigma 8(\frac{1}{10})^{n-1}$ $|r|=\frac{1}{10}<1$ Convergent $a=8$ $S=\frac{8}{9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.