#### Answer

This geometric series diverges.

#### Work Step by Step

Since the given series is in a similar form as the definition of the geometric series that can be found in page 750 definition 4 -second line in the page- (we can make it very close by taking one 3 outside so $3^{n+1}$ becomes $3^{n}$).
The summation of an infinite geometric series is $S= \frac{a}{1-r}$ if |$r$| $\lt 1 $ , here $r$ is the common ratio of the geometric series.
Now, If we choose n = 0 we can see that the initial term $a$ = $3$ and the common ratio $r$ = $\frac{-3}{2}$ (Just by looking at the form in definition and the one in the question after factoring out a $3$).
$r$ = |$\frac{-3}{2}$| $\gt 1 $ , which means the series is divergent.
The answer is:
This geometric series diverges.