## Calculus 8th Edition

If we look at the ratio change from term to term we find that: 3$* \frac{-4}{3}$= -4 , and -4 * $\frac{-4}{3}$ = $\frac{16}{3}$ and so on, thus we have $r = \frac{-4}{3}$ looking at the formulas and definition 4. in page 750, we find that $| \frac{-4}{3} | \geq1$. Result: the series diverges.
Since we are given the information in the question that the series is geometric, we look for the common ratio. To do that, we can divide the terms. For example: $\frac{-64}{9} \div \frac{16}{3} = \frac{-4}{3}$ Same for the third term divided by the second: $\frac{16}{3} \div -4 = \frac{-4}{3}$. Then, after finding the ratio, we look at definition 4 and its formulas in page 750 and we observe that $| r | = \frac{4}{3} \geq1$. which means that the series diverges (which, for explanation, means that the series sum goes to infinity as the number of terms increase)