Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.2 Series - 11.2 Exercises: 39

Answer

the series diverges

Work Step by Step

nth term test of divergence: if $\lim\limits_{n \to \infty} {a_{n}} \ne 0$, then the series $\Sigma a_{n}$ diverges. In the problem $a_{n} = arctan(n)$ $\lim\limits_{n \to \infty} arctan(n) = \frac{\pi}{2}$ Since $ \frac{\pi}{2} \ne 0$, the series $\sum_{n}^{\infty} \arctan n $ diverges.
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