Calculus 8th Edition

$5x+4y-15=0$ for $-5≤x≤7$
$m = \frac{y_2-y_1}{x_2-x_1}=\frac{10-(-10)}{-5-7} = \frac{20}{-12}=\frac{-5}{4}$ $y-y_1=m(x-x_1)$ Using point (-5,10) $y - 10 = \frac{-5}{4}(x-(-5))$ $4y-40 = -5x -25$ $5x+4y-15=0$ Since this is only over the range of (-5,10) to (7,-10) this applies only to the domain of $-5≤x≤7.$