## Calculus 8th Edition

{ x | -2 $\leq$ x $\leq$ 3}
Since $\sqrt x$ is valid only if x $\geq$ 0, we must have: 3 - t $\geq$ 0 3 $\geq$ t t $\leq$ 3 and 2 + t $\geq$ 0 t $\geq$ -2 We conclude that: { x | -2 $\leq$ x $\leq$ 3}