## Calculus 8th Edition

$f(-3) = -2$ $f(0) = 0$ $f(2) = 4$ and the graph is in the picture.
if $x\leq-1$ then $f(x)=x+1$ if $x\gt-1$ then $f(x)=x^{2}$ So $-3\leq-1$ so $f(-3) =-3+1 = -2$ $0 \gt -1$ so $f(0) =0^{2} = 0$ $2 \gt -1$ so $f(2) = 2^{2} = 4$ and the graph is in the picture.