## Calculus 8th Edition

The domain is $-2 \leq x \leq 2$ the range: $[0, 2]$ The sketch is the picture
$h(x) = \sqrt {4-x^{2}}$ Lets find the domain $4-x^{2} \geq 0$ $4 \geq x^{2}$ $-2 \leq x \leq 2$ So the domain is $-2 \leq x \leq 2$ the range is between $\sqrt 4$ and $\sqrt 0$ the range: $[0, 2]$ The sketch is the picture