## Calculus 8th Edition

The Domain is $t \ne -1$ the Range is: $(-\infty, -2) and (-2, \infty)$ The sketch is:
$g(t) = \frac{t^2 - 1}{t + 1}$ Lets find the Domain of the function $t+1\ne0$ $t \ne -1$ The Domain is $t \ne -1$ Lets find the Range: $g(t) = \frac{t^2 - 1}{t + 1} = \frac{(t-1)(t+1)}{t + 1}$ when $t \ne -1$, $g(t) =(t-1)$ So the Range is: $(-\infty, -2) and (-2, \infty)$ The sketch is: