## Calculus 8th Edition

-1 + $\frac{1}{3}$ + $\frac{3}{5}$+$\frac{5}{7}$+$\frac{7}{9}$
k starts at 0 (k=0), and every iteration it increases by one until it reaches 4(n). $\frac{2(0)-1}{2(0)+1}$ + $\frac{2(1)-1}{2(1)+1}$ + $\frac{2(2)-1}{2(2)+1}$ + $\frac{2(3)-1}{2(3)+1}$ + $\frac{2(4)-1}{2(4)+1}$.