Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix E - Sigma Notation - E Exercises: 27

Answer

$61$

Work Step by Step

We expand and simplify the sum: $\displaystyle \sum_{i=0}^{4}(2^{i}+i^{2})$ $=(2^0+0^2)+(2^1+1^2)+(2^2+2^2)+(2^3+3^2)+(2^4+4^2)$ $=(1+0)+(2+1)+(4+4)+(8+9)+(16+16)$ $=61$
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