Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix E - Sigma Notation - E Exercises - Page A38: 37

Answer

$\sum\limits_{i =1}^{n}c=nc$

Work Step by Step

Theorem 3(b) defines as $\sum\limits_{i =1}^{n}c=nc$ The left side can be written as $\sum\limits_{i =1}^{n}c=c+c+c+c+c....+c$ (n- times) Since, $c$ has been added n-times thus, it can be generally multiplied by $n$ such as $nc$. Hence, $\sum\limits_{i =1}^{n}c=nc$
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