Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 387: 89


$$\frac{1}{4}(\sinh x)^4+c$$

Work Step by Step

Let $u=\sinh x$, then $du=\cosh xdx$. Now, we have $$\int (\sinh x)^3\cosh xdx=\int u^3du=\frac{1}{4}u^4+c\\ =\frac{1}{4}(\sinh x)^4+c$$
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