Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 387: 73

Answer

$\frac{1}{2}$

Work Step by Step

Let $ u=\ln x $, then $ du=\frac{1}{x}dx $. Now, we have $$\int_1^e \frac{\ln x}{x}dx =\int_0^1 udu = \frac{1}{2}u^2|_0^1\\ =\frac{1}{2}(1-0)=\frac{1}{2}.$$
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