Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 387: 71



Work Step by Step

Let $ u=4x-3$, then $ du=4dx $. Now, we have $$\int_1^3 e^{4x-3}dx =\frac{1}{4} \int_1^9 e^udu = \frac{1}{4} e^u|_1^9=\frac{1}{4}(e^9-e).$$
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