Answer
$$\int \frac{(\ln x)^2}{x}dx =\frac{1}{3}(\ln x)^3+c.$$
Work Step by Step
Since $ u=\ln x $, then $ du= \frac{dx}{x}$ and hence
$$\int \frac{(\ln x)^2}{x}dx=\int u^2du=\frac{1}{3}u^3+c=\frac{1}{3}(\ln x)^3+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 387: 61
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