Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 89



Work Step by Step

Since $(e^{3x})'=3e^{3x}$, then we have $$ \int\frac{e^{2x}-e^{4x}}{e^{x}} d x=\int e^{x}-e^{3x}d x \\ =e^{x}-\frac{1}{3}e^{3x}+c. $$
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