Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 74


$$\frac{1}{3}\ln (3x+5)+c .$$

Work Step by Step

Let $u=3x+5$, then $du=3dx$. Now, we have $$\int \frac{dx}{3x+5}=\frac{1}{3}\int \frac{du}{u}=\frac{1}{3}\ln u+c=\frac{1}{3}\ln (3x+5)+c .$$
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