Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 54



Work Step by Step

We have $$\int^7_2\frac{xdx}{x^2+1}=\frac{1}{2}\int^7_2\frac{2xdx}{x^2+1}=\frac{1}{2}\ln(x^2+1)|^7_2\\ =\frac{1}{2}\ln50 -\frac{1}{2}\ln5=\frac{1}{2}\ln\frac{50}{5}=\frac{1}{2}\ln10.$$
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