Answer
$$\ln (\sin x)+c.$$
Work Step by Step
Using the fact that $\int u'/u=\ln u$, we have
$$\int \cot x dx=\int \frac{1}{\tan x }dx =\int \frac{\cos x}{\sin x}dx\\
=\ln (\sin x)+c.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 101
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