Answer
$\frac{\pi}{6}$
Work Step by Step
We have
$$\int^{1/2}_0\frac{ dx}{\sqrt{1-x^2}}=\sin^{-1}x|^{1/2}_0\\
=\sin^{-1}\frac{1}{2}-\sin^{-1}0=\frac{\pi}{6}-0=\frac{\pi}{6}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 55
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