Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.1 Derivative of f(x)=bx and the Number e - Exercises - Page 327: 47

Answer

$ x=0$, local minima at $ x=0$.

Work Step by Step

To find the critical point we put $ f'(x)=0$, so we have $$ f(x)=e^x-x\Longrightarrow f'(x)=e^x-1=0,$$ then $ e^x=1$ and hence $ x=0$. So the critical point is $ x=0$. Moreover, we have $$ f''(x)=e^x\Longrightarrow f''(0)=1>0$$ then $ f(x) $ has local minima at $ x=0$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.