## Calculus (3rd Edition)

$$t=1, \quad t=3.$$
Since the bases are equal, then the exponents are equal. Hence, $$t^2=4t-3\Longrightarrow t^2-4t+3=0 \Longrightarrow (t-1)(t-3)=0.$$ Then, $$t=1, \quad t=3.$$