## Calculus (3rd Edition)

$$f''(x)= 16 e^{4x-3}.$$
Recall that $(e^x)'=e^x$ Since we have $$f(x)= e^{4x-3}$$ then the first derivative $f'(x)$, using the chain rule, is given by $$f'(x)= e^{4x-3}(4x-3)'=4 e^{4x-3}.$$ The second derivative $f''(x)$ is given by $$f''(x)= 4 e^{4x-3}(4x-3)'=16 e^{4x-3}.$$