## Calculus (3rd Edition)

$\frac{1}{2}$
We know that $16=2^4$. Hence $\left(16^{-\frac{1}{16}}\right)^4=16^{-\frac{1}{16}\cdot4}=16^{-\frac{1}{4}}=(2^4)^{-\frac{1}{4}}=2^{(4\cdot-\frac{1}{4})}=2^{-1}=\frac{1}{2}$